2[d-(4d+12)+2]=2(d+10)

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Solution for 2[d-(4d+12)+2]=2(d+10) equation:


Simplifying
2[d + -1(4d + 12) + 2] = 2(d + 10)

Reorder the terms:
2[d + -1(12 + 4d) + 2] = 2(d + 10)
2[d + (12 * -1 + 4d * -1) + 2] = 2(d + 10)
2[d + (-12 + -4d) + 2] = 2(d + 10)

Reorder the terms:
2[-12 + 2 + d + -4d] = 2(d + 10)

Combine like terms: -12 + 2 = -10
2[-10 + d + -4d] = 2(d + 10)

Combine like terms: d + -4d = -3d
2[-10 + -3d] = 2(d + 10)
[-10 * 2 + -3d * 2] = 2(d + 10)
[-20 + -6d] = 2(d + 10)

Reorder the terms:
-20 + -6d = 2(10 + d)
-20 + -6d = (10 * 2 + d * 2)
-20 + -6d = (20 + 2d)

Solving
-20 + -6d = 20 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-20 + -6d + -2d = 20 + 2d + -2d

Combine like terms: -6d + -2d = -8d
-20 + -8d = 20 + 2d + -2d

Combine like terms: 2d + -2d = 0
-20 + -8d = 20 + 0
-20 + -8d = 20

Add '20' to each side of the equation.
-20 + 20 + -8d = 20 + 20

Combine like terms: -20 + 20 = 0
0 + -8d = 20 + 20
-8d = 20 + 20

Combine like terms: 20 + 20 = 40
-8d = 40

Divide each side by '-8'.
d = -5

Simplifying
d = -5

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